1st place Mousetrap Car Ideas

When we did this in highschool our speed/acceleration contest was only over a meter, so I just used the mouse trap to catapult my car over the finish line.

The internet needs more people like Mark Rober. Youtube should give incentives for NASA employees to become creators.

Can you imagine how lucky some future kid is gonna be to be able to call Mark Rober their physics teacher??

in my 8th grade science class we are actually doing something where you can either build a lander or a rover, no electricity and stuff like that. I had the egg drop thing as an idea for a lander and this for a rover and I'm super excited to test both out and see which one is better.

I wish Mark was my physics teacher...

The way Mark explains physics is not only easier to understand than school ever taught me but he makes it so much more interesting

It’s almost 2022 and I’m still enjoying this video, I mean the way Mark explains engineering is so amazing.

this has sat in my brain for 3 years and has silently been supporting me through my physics classes. Thank you.

- Dad, why is my sister called Rose? - Because your mother loves flowers. - Oh ok, thanks dad.. - No problem, Mechanical Advantage.

“Thank yo-“ Niece: ** Slaps Ice Cream ** “O WOAAH”

no one is talking about how mark was outside IN THE RAIN for a bit just so he can explain the topic he was on. I want him to be my teacher.

I never did this as a kid but being an auto mechanic now I got a huge kick out of this video! Made me think about the mathematics of transmissions and differential final drive ratios. Super fun keep up the great work!

When mr. Rober is a physics teacher to almost 10 million people and doesn't realize it.

I learned more in the first 5 minutes than a whole semester in high school

Wonderful! From your intro, I thought you were going to make your own design, better than any other. Even so, I enjoyed the lesson.

Hey Mark! Nice Video. I wanted to point out that, at 2:03, mechanical advantage doesn't necessarily equal number of pulleys in all pulley systems. This is because fixed pulleys (pulleys which don't move while the load does) have a mechanical advantage of 1, while movable pulleys (pulleys which do move while the load does) have a mechanical advantage of 2. This is why, in your case, the pulley system had a mechanical advantage of 4: the specific arrangement and positioning of 2 movable and 2 fixed pulleys allowed the system to have a mechanical advantage of 4. However, it is important to note that this doesn't happen to all arrangements of 4 pulleys, as if you were to line up 4 fixed pulleys, you would still get an mechanical advantage of 1, not 4. Thus, you cannot say that mechanical advantage equals number of pulleys in all pulley systems. Instead, you could "split" up the tension along the ropes of a pulley through a diagram. Here's the procedure: you first can imagine that you are holding the end of whatever pulley system you are trying to solve with such a force such that the system is in static equilibrium. Next, you can split the tension caused by the force of the load among the ropes of the pulley system. The key to remember is that each unbroken piece of rope will have uniform tension along it. Finally, you keep splitting the tension all the way until you reach the rope which you are holding. The mechanical advantage of the pulley system will simply be the the load force divided by the effort force, which is simply equal to the tension in that rope you are holding, since the system is in static equilibrium. THAT is the correct way to solve for the mechanical advantage of a pulley system (sorry if I explained it badly). Additionally, I wanted to point out that, at 2:08, mechanical advantage of an inclined plane does not equal the ratio of the length to the height unless the inclined plane is just flat and not inclined, in which case I wouldn't really call it an "inclined" plane. But instead, mechanical advantage of an inclined plane is equal to the ratio of the hypotenuse to the height. This can be derived like this: the load force on the inclined plane is simply equal to its downward force caused by gravity, which is simple equal to f = ma = mg. We can split this force into its x- and y- components, which we can then deduce that the force of the load in the direction parallel to and going down the hypotenuse of the inclined plane is equal to mgsin(theta), in which theta is the angle of the elevation of the inclined plane. This means that, if we were to push the load up on the inclined plane with force mgsin(theta), then the system would achieve static equilibrium. In other words, the load would stay in place. Since we know that mechanical advantage is defined as the ratio of the output force to the input force, that would simply mean that the mechanical advantage of the inclined plane would be mg/mgsin(theta), as mg is the output force in this case and mgsin(theta) is the input force in this case. This simplifies to 1/sin(theta). This is simply equal to the ratio of the hypotenuse to the side opposite angle theta, which in this case is height. Thus, mechanical advantage of an inclined plane is equal to the ratio of the hypotenuse to the height.

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Breaking news: Worker in NASA go to school to totally annihilate kids in mousetrap car race

I think I just found a lifetime hobby. Every science teacher I’ve ever had said I possess an extremely intuitive understanding of physics and this seems to be a perfect application of that. Just seeing this video makes my mind go crazy thinking of all the ways I could attempt to improve the design. I wonder if you could devise an equation that could predictably determine what the optimal ratio of mechanical advantage for a given car would be, accounting for factors like weight, wheel diameter, coefficient of friction on the wheels, axels, and every other moving part where friction is present. Obviously there’s a perfectly optimal car that could be made if you could fully understand all these factors and that’s what is most alluring to me.